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Let O and H be the circumcenter and orthocenter of acute triangle ABC, respectively. If the sum for the degrees of angle AHC and angle AOC is 240 degrees what is the measure of angle ABC in degrees?

 Nov 7, 2019
 #2
avatar+105971 
+2

Hi Noobmaster69,

 

Let O and H be the circumcenter and orthocenter of acute triangle ABC, respectively.

If the sum for the degrees of angle AHC  (orange) and angle AOC (pink) is 240 degrees

what is the measure of angle ABC  in degrees?   (black)

 

 

Here is the pic

The  pink plus orange angles add up to 240 degrees and I have to find the size of the black angle.  

My pic in not to scale, I mean my pink and orange ones do not add up to 240. 

Other than that I think my pic is a proper indication of the problem at hand.

 

Let the black angle be called alpha       \(\angle CBA=\alpha\)

Consider minor arc CA

< COA is the angle at the centre standing on arc CA    ....  that is the pink angle

< CBA  is the angle at the circumferecne standing on arc CA    ....  that is the black  angle 

so since the angle at the centre = 2 times the angle at the circumference when both are staning on the same arc,  

BLACK    \(\angle CBA=\alpha\)

Pink         \(\angle COA=2\alpha\)

 

 

 

 

 

 

 

NOW  look at the new image below.

Consider the green triangle \(\triangle IBA\) and the yellow triangle \(\triangle KHA\)

angle AIB = angle AKH = 90 degrees

angle at A is a common angle

therefore these two triangles are similar which means that   \(\angle IBA=\angle KHA = \alpha\)

 

Now I have 


\(\angle CHA+\angle KHA = 180\\ \angle CHA+\alpha = 180\\ orange + \alpha =180 \;degrees\\ orange \;angle=(180-\alpha) \;degrees\\\)

I also know that

 

 \(orange+pink=240\\ (180-\alpha)+(2\alpha)=240\\ 180+\alpha=240\\ \alpha=60\;degrees\)

 

Therefore, angle ABC=60 degrees

 

 

 

 

 

 

 

I know my logic is correct but i hope i have not made a mistake during the presentation.

Plus

There may well have been a much simpler way to do it.

 Nov 7, 2019
edited by Melody  Nov 7, 2019
 #3
avatar+19726 
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YIKES!    I had no inclination....or know-how .....to answer THIS one !

Nice , Melody ! 

 Nov 9, 2019
 #4
avatar+105971 
0

Thanks EP.

It was a bit confusing. I just like drawing these pics and if I can get the pic right then I have some chance of answering the question.

Although I will admit that Chris is better at geometry than I am.

 

It took me AGES to draw it!    wink

Melody  Nov 9, 2019
 #5
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+1

Hi Melody

I've made a start on learning how to draw things with GeoGebra.

In your diagram, I know how to get those rt angle and other angles thingy's, but could you tell me 

how you colour areas ?

How did you make the triangle area AHK yellow, for example ?

Guest Nov 9, 2019
 #6
avatar+105971 
+1

I write click on the object to select it.

Then i wright click and select 'settings'

Go into settings and have a play.   laugh

 

 

 

 

 

OR

If you just want to change the colour and not twig other properies, you can click on the triangle to select it and 

a box will appear in the top write corner where you can change the colour.

 

 

It took me a long time to be comfortable using Geogebra. Even now I occasionally discover new features.

I think it is a lot of fun to use.

Melody  Nov 9, 2019
 #7
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+1

Thanks for info Melody., I shall try that.

Guest Nov 9, 2019

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