So I have an equation the square root of 5x^2-7= 2x. How do I solve for x?
+23247 If this is the problem:
√(5x2 - 7) = 2x
Square both sides:
---> 5x2 - 7 = (2x)2
5x2 - 7 = 4x2
Subtract 5x2 from both sides:
---> -7 = -x2
Divide both sides by -1:
---> 7 = x2
Find the square root of both sides:
---> x = ±√7
However, if you check by placing both √7 and -√7 into the original equation, only √7 works.
+23247 If this is the problem:
√(5x2 - 7) = 2x
Square both sides:
---> 5x2 - 7 = (2x)2
5x2 - 7 = 4x2
Subtract 5x2 from both sides:
---> -7 = -x2
Divide both sides by -1:
---> 7 = x2
Find the square root of both sides:
---> x = ±√7
However, if you check by placing both √7 and -√7 into the original equation, only √7 works.
