I need help solving \(tan(2\theta)=1\)within \(0 \leq \theta \leq 2\pi\)
If you could also provide how to do it, that would be helpful
tan[theta] = 1 ... at pi/4, 5pi/4, 9pi/4 and 13pi/4
So......dividing each angle by 2
tan [ 2* theta] = 1 at pi/8, 5pi/8 , 9pi/8 and 13pi/8
