Solve. 10p^2-41p=0?

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Solve. 10p^2-41p=0?

Guest Dec 10, 2014

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Best Answer

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$${\mathtt{10}}{\mathtt{\,\times\,}}{{\mathtt{p}}}^{{\mathtt{2}}}{\mathtt{\,-\,}}{\mathtt{41}}{\mathtt{\,\times\,}}{\mathtt{p}} = {\mathtt{0}} \Rightarrow \left\{ \begin{array}{l}{\mathtt{p}} = {\frac{{\mathtt{41}}}{{\mathtt{10}}}}\\
{\mathtt{p}} = {\mathtt{0}}\\
\end{array} \right\} \Rightarrow \left\{ \begin{array}{l}{\mathtt{p}} = {\mathtt{4.1}}\\
{\mathtt{p}} = {\mathtt{0}}\\
\end{array} \right\}$$

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happy7 Dec 10, 2014

1⁺⁰ Answers

+7188

+8

Best Answer

$${\mathtt{10}}{\mathtt{\,\times\,}}{{\mathtt{p}}}^{{\mathtt{2}}}{\mathtt{\,-\,}}{\mathtt{41}}{\mathtt{\,\times\,}}{\mathtt{p}} = {\mathtt{0}} \Rightarrow \left\{ \begin{array}{l}{\mathtt{p}} = {\frac{{\mathtt{41}}}{{\mathtt{10}}}}\\
{\mathtt{p}} = {\mathtt{0}}\\
\end{array} \right\} \Rightarrow \left\{ \begin{array}{l}{\mathtt{p}} = {\mathtt{4.1}}\\
{\mathtt{p}} = {\mathtt{0}}\\
\end{array} \right\}$$

happy7 Dec 10, 2014

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