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 solve 3^(x-1) ≤ 2^x-7? is this possible with log

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solve 3^(x-1) ≤ 2^x-7? is this possible with log

 Jan 25, 2018

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 #1
avatar+128474 
+2

WolframAlpha finds no real solutions to this......

 

cool cool cool

 Jan 25, 2018
 #2
avatar+118609 
+2

Here is the graph. From the graph it certainly appears that  3^(x-1) will always be bigger than 2^x-7

 

 

 

 Jan 25, 2018

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