Solve 3A+4C=159 2A+3C=112

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Solve 3A+4C=159 2A+3C=112

Math58 Nov 30, 2014

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Best Answer

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3A+4C=159 (1a)→ x 2 → 6A+8C=318 (1B)

2A+3C=112 (2a) → x 3 → 6A+9C=336 (2B)

(2B)-(1B)

C=18

Sub C=18 into (2a)

You should be able to finish it. But if you have problems add a post to this thread. :)

Melody Nov 30, 2014

1⁺⁰ Answers

+118687

+5

Best Answer

3A+4C=159 (1a)→ x 2 → 6A+8C=318 (1B)

2A+3C=112 (2a) → x 3 → 6A+9C=336 (2B)

(2B)-(1B)

C=18

Sub C=18 into (2a)

You should be able to finish it. But if you have problems add a post to this thread. :)

Melody Nov 30, 2014

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