\(\frac{5n}{5n}=1 \)
Anything divided by itself is 1 except 0 which is undefined.
Proof by multiplication & exponentials.. :
Assume:
\((5n)^{1}*(5n)^{-1}=\frac{5n}{5n}\)
Then,
\(5n^{1}*5n^{-1}\) Notice same bases so and multiplication so we add power
\((5n)^{1+(-1)}=(5n)^0=5^0n^0=1*1=1\)
Standard form is :
\(A*10^n\)
Where,
\(0 A is an integer more than zero and less than 10, so A could be these only \(({1,2,3,4,5,6,7,8,9})\)
Your question says how would "2011" appear in standard form"
note that if A.bcks..
If these letters after A aren't 0 then you must write them as decimals and the number of them (the decimals) is n (Which is the power of 10)
I.e.
\(1972\) in standard form is \(1.972*10^3\)
Notice A is in the range and after it 3 numbers (Decimals) thus the 10 is to power 3
\(2011=2.011*10^3\)Positive power moves decimal mark to the right, negative power moves it to the left.
