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# solve 5n/5n

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solve 5n/5n

Jan 21, 2020

#1
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$$\frac{5n}{5n}=1$$

Anything divided by itself is 1 except 0 which is undefined.

Proof by multiplication & exponentials.. :

Assume:

$$(5n)^{1}*(5n)^{-1}=\frac{5n}{5n}$$

Then,

$$5n^{1}*5n^{-1}$$ Notice same bases so and multiplication so we add power

$$(5n)^{1+(-1)}=(5n)^0=5^0n^0=1*1=1$$

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Jan 21, 2020
#5
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Standard form is :

$$A*10^n$$

Where,

$$0 A is an integer more than zero and less than 10, so A could be these only \(({1,2,3,4,5,6,7,8,9})$$

Your question says how would "2011" appear in standard form"

note that if A.bcks..

If these letters after A aren't 0 then you must write them as decimals and the number of them (the decimals) is n (Which is the power of 10)

I.e.

$$1972$$ in standard form is $$1.972*10^3$$

Notice A is in the range and after it 3 numbers (Decimals) thus the 10 is to power 3

$$2011=2.011*10^3$$Positive power moves decimal mark to the right, negative power moves it to the left.

Guest Jan 21, 2020
#2
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how would the year 2011 appear in standard form

Jan 21, 2020
#3
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how would the year 2011 appear in standard form

Jan 21, 2020
#4
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how would the year 2011 appear in standard form

Jan 21, 2020
#6
+107414
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