+0  
 
0
41
7
avatar

solve 5n/5n

 Jan 21, 2020
 #1
avatar
+1

\(\frac{5n}{5n}=1 \)

Anything divided by itself is 1 except 0 which is undefined. 

Proof by multiplication & exponentials.. :

Assume:

\((5n)^{1}*(5n)^{-1}=\frac{5n}{5n}\)

Then,

\(5n^{1}*5n^{-1}\) Notice same bases so and multiplication so we add power 

\((5n)^{1+(-1)}=(5n)^0=5^0n^0=1*1=1\)

.
 Jan 21, 2020
 #5
avatar
+1

Standard form is : 

\(A*10^n\)

Where,

\(0  A is an integer more than zero and less than 10, so A could be these only \(({1,2,3,4,5,6,7,8,9})\)

Your question says how would "2011" appear in standard form" 

note that if A.bcks.. 

If these letters after A aren't 0 then you must write them as decimals and the number of them (the decimals) is n (Which is the power of 10)

I.e.

\(1972\) in standard form is \(1.972*10^3\)

Notice A is in the range and after it 3 numbers (Decimals) thus the 10 is to power 3

 

\(2011=2.011*10^3\)Positive power moves decimal mark to the right, negative power moves it to the left.

Guest Jan 21, 2020
 #2
avatar
0

how would the year 2011 appear in standard form

 Jan 21, 2020
 #3
avatar
0

how would the year 2011 appear in standard form

 Jan 21, 2020
 #4
avatar
0

how would the year 2011 appear in standard form

 Jan 21, 2020
 #6
avatar+107414 
0

That is already answered.

Melody  Jan 21, 2020
 #7
avatar
0

Hi Melody,

He spammed it 3 times (Maybe lag when I answered) 

Guest Jan 21, 2020

26 Online Users

avatar
avatar
avatar
avatar