Solve the following system:
{6 x+6 y = 12 | (equation 1)
y-6 x = 23 | (equation 2)
Add equation 1 to equation 2:
{6 x+6 y = 12 | (equation 1)
0 x+7 y = 35 | (equation 2)
Divide equation 1 by 6:
{x+y = 2 | (equation 1)
0 x+7 y = 35 | (equation 2)
Divide equation 2 by 7:
{x+y = 2 | (equation 1)
0 x+y = 5 | (equation 2)
Subtract equation 2 from equation 1:
{x+0 y = -3 | (equation 1)
0 x+y = 5 | (equation 2)
Collect results:
Answer: |x = -3 and y = 5
