3x^2=-33x-90
it's alright thanks for atleast looking at it.
i cant solve i have no idea what factoring is much less how to do it.
\(\begin{array}{lcl}3x^2=-33x-90\\ 3x^2+33x+90=0 \text{ (:3)}\\ x^2+11x+30=0\\ (x+6)(x+5)=0\\ x_1=-5\\ x_2=-6 \end{array}\)
here is full answer by cymath:
http://www.cymath.com/answer.php?q=3x%5E2%3D-33x-90
thanks Solveit that helps
