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Please help

 Nov 29, 2016

Best Answer 

 #1
avatar+118654 
+5

lnx<0

 

\(lnx<0\\ e^{lnx}<e^0\\ x<1\)

 

BUT x cannot be less than or equal to 0 so

 

\(0<x<1\)

 

Here is the graph to show that this is correct

 Nov 30, 2016
 #1
avatar+118654 
+5
Best Answer

lnx<0

 

\(lnx<0\\ e^{lnx}<e^0\\ x<1\)

 

BUT x cannot be less than or equal to 0 so

 

\(0<x<1\)

 

Here is the graph to show that this is correct

Melody Nov 30, 2016
 #2
avatar+118654 
+5

e^x>3

 

\(e^x>3\\ ln(e^x)>ln3\\ xln(e)>ln3\\ x>ln3\\\)

 

Here is the graph

 

 Nov 30, 2016

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