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solve fo y

 

1/3(y+2)=1/5(2y+3)

 May 18, 2016
 #1
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Solve for y:
(y+2)/3 = (2 y+3)/5

 

Multiply both sides by 15:
(15 (y+2))/3 = (15 (2 y+3))/5

 

15/3 = (3×5)/3 = 5:
5 (y+2) = (15 (2 y+3))/5

 

15/5 = (5×3)/5 = 3:
5 (y+2) = 3 (2 y+3)

 

Expand out terms of the left hand side:
5 y+10 = 3 (2 y+3)

 

Expand out terms of the right hand side:
5 y+10 = 6 y+9

 

Subtract 6 y from both sides:
(5 y-6 y)+10 = (6 y-6 y)+9

 

5 y-6 y = -y:
-y+10 = (6 y-6 y)+9

 

6 y-6 y = 0:
10-y = 9

 

Subtract 10 from both sides:
(10-10)-y = 9-10

 

10-10 = 0:
-y = 9-10

 

9-10 = -1:
-y = -1

 

Multiply both sides of -y = -1 by -1:
-y/(-1) = (-1)/(-1)

 

(-1)/(-1) = 1:
y = (-1)/(-1)

 

(-1)/(-1) = 1:
Answer: |  y = 1

 May 18, 2016

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