Determine whether the equation has one solution, no solution, or infinitely many solutions.
Simplify:
\(3n-2 = 2n-6\)
Subtract \(2n\):
\(n-2=-6\)
Add 2:
\(n = -4\)
The equation has only \(\color{brown}\boxed{1}\) solution
Builder, you miscopied the original equation.
The OP wrote 3n + 2 = 2(n – 3)
You wrote it as 3n – 2 = 2(n – 3)
Solving 3n + 2 = 2(n – 3)
3n + 2 = 2n – 6
n + 2 = –6
n = –8 one solution
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