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Solve for a.

\sqrt(p+a+r=k)

Nov 1, 2019

#1
+973
+2

I assume you mean $$\sqrt{p+a+r}=k$$.

Whenever there is a square root symbol, you want to square the equation.

$$(\sqrt{p+a+r})^2=k^2$$

This becomes $$p+a+r=k^2$$, because the square root symbol is lifted.

Now we can add and subtract values on each side of the equation to find a. I think you can do that.

You are very welcome!

:P

Nov 1, 2019

#1
+973
+2

I assume you mean $$\sqrt{p+a+r}=k$$.

Whenever there is a square root symbol, you want to square the equation.

$$(\sqrt{p+a+r})^2=k^2$$

This becomes $$p+a+r=k^2$$, because the square root symbol is lifted.

Now we can add and subtract values on each side of the equation to find a. I think you can do that.

You are very welcome!

:P

CoolStuffYT Nov 1, 2019