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Solve for I.

\(9x+I<3(3x+u)\)

AdamTaurus  Nov 8, 2017

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 9 x + I<3 (3 x + u) [Is I supposed to be the imaginary i??. If so, then inequalities are not well-defined in the complex plane (the field of complex numbers is not totally-ordered).

9x + I < 9x + 3u  subtract 9x from both sides

I < 3u                    and u element R.

Guest Nov 8, 2017
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 #1
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Best Answer

 9 x + I<3 (3 x + u) [Is I supposed to be the imaginary i??. If so, then inequalities are not well-defined in the complex plane (the field of complex numbers is not totally-ordered).

9x + I < 9x + 3u  subtract 9x from both sides

I < 3u                    and u element R.

Guest Nov 8, 2017

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