Loading [MathJax]/jax/output/SVG/config.js

Solve for x. log(5)(2x+1)=1

0

1349

1

log(5)(2x+1)=1

Guest Apr 24, 2015

Best Answer

+130458

+5

log₅ (2x + 1) = 1

In exponential form, we have

5¹ = 2x + 1

5 = 2x + 1 subtract 1 from both sides

4 = 2x divide by 2 on both sides

x = 2

CPhill Apr 25, 2015

1⁺⁰ Answers

+130458

+5

Best Answer

log₅ (2x + 1) = 1

In exponential form, we have

5¹ = 2x + 1

5 = 2x + 1 subtract 1 from both sides

4 = 2x divide by 2 on both sides

x = 2

CPhill Apr 25, 2015

1 Online Users