Solve for x.... log5A^x=log3B
A. x=log5(A/B)
B. x=log5(B/A)
C. x= log3B / log5A
D. x= log5A / log3B
E. none of these
log5A^x=log3B .....we can write
x log5A = log3B divide both sides by log5A
x = log3B / log5A
+128 
