Solve for x:
\([\frac{x^2+2x+3}{x+4}=x+5]\)
[ x^2 + 2x + 3] / [ x + 4] = [ x + 5] multiply both sides by x + 4
x^2 + 2x + 3 = x^2 + 9x + 20 subtract x^2 from both sides
2x + 3 = 9x + 20 subtract, 9x, 3 from both sides
-7x = 17 divide both sides by -7
x = -17 / 7