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ln(x+3)=ln4+ln(x-3)

I've been having trouble with this problem. I keep on getting x+2=x
 Feb 13, 2014
 #1
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What does "In" stand for? Is it a variable? If so, you can't solve the problem because there are two variable and we don't know the value of either. Please clarify on this bit so I can try to help!

Warm Regards,
Grammar Fascist
 Feb 13, 2014
 #2
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Ln is supposed to be log.
 Feb 13, 2014
 #3
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zethwolf:

ln(x+3)=ln4+ln(x-3)

I've been having trouble with this problem. I keep on getting x+2=x



This is a page that i always keep handy.

http://en.wikipedia.org/wiki/List_of_logarithmic_identities

How about
ln(x+3) - ln(x-3) = ln4

ln{ (x+3)/(x-3) } = ln4

(x+3)/(x-3) = 4

x+3 = 4(x-3)
.....
x=5

That was a tricky one
 Feb 13, 2014
 #4
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Thanks so much Melody!
 Feb 13, 2014

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