zethwolf: ln(x+3)=ln4+ln(x-3)
I've been having trouble with this problem. I keep on getting x+2=x
This is a page that i always keep handy.
http://en.wikipedia.org/wiki/List_of_logarithmic_identities
How about
ln(x+3) - ln(x-3) = ln4
ln{ (x+3)/(x-3) } = ln4
(x+3)/(x-3) = 4
x+3 = 4(x-3)
.....
x=5
That was a tricky one