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Solve for x:

$ \frac{3x+12}{x+4} = \frac{4x^2 + 8x + 8x^2}{2x}$

 Jul 5, 2015

Best Answer 

 #1
avatar+128481 
+6

[ 3x + 12 ] /  [ x + 4 ] =  [4x^2 + 8x + 8x^2] / [ 2x]     simplify and combine terms

 

3[ x + 4] / [ x + 4 ]  =  [ 12x^2 + 8x] . [2x] 

 

3   =  4x [ 3x + 2 ] ] [2x]

 

3  = 2[3x + 2 ]

 

3  = 6x + 4      subtract 4 from both sides

 

-1   = 6x        divide by 6 on both sides

 

-1/6 =  x

 

 

 Jul 6, 2015
 #1
avatar+128481 
+6
Best Answer

[ 3x + 12 ] /  [ x + 4 ] =  [4x^2 + 8x + 8x^2] / [ 2x]     simplify and combine terms

 

3[ x + 4] / [ x + 4 ]  =  [ 12x^2 + 8x] . [2x] 

 

3   =  4x [ 3x + 2 ] ] [2x]

 

3  = 2[3x + 2 ]

 

3  = 6x + 4      subtract 4 from both sides

 

-1   = 6x        divide by 6 on both sides

 

-1/6 =  x

 

 

CPhill Jul 6, 2015

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