#1**0 **

Input: b(5px-3c) = a(qx-4)

Intepretation: Solve for \(x\) in \(\)\(b(5px+3c) = a(qx-4)\)

Expand:

\(5bpx-3bc=aqx-4a\)

Move the \(x\) terms to the right, integer ones to the left:

\(5bpx-aqx=3bc-4a\)

Pull the x out from the left term:

\((5bp-aq)x=3bc-4a\)

Divide both sides by \(5bp-aq\):

\(x=\frac{3bc-4a}{5bp-aq}\)

Done :D

Jeffes02
Aug 20, 2017