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3ax/5 - 4c = ax/5

Guest Aug 20, 2017
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Input: 3ax/5 - 4c = ax/5

Intepretation: \(\frac{3ax}{5}-4c=\frac{ax}{5}\)

Multiply by \(5\) on both sides:

\(3ax-20c=ax\)

Move the \(x\) term to the left, numeric ones to the right:

\(3ax-ax=20c\)

Simplify:

\(2ax=20c\)

Divide by \(2\) on both sides:

\(ax=10c\)

Finally, divide \(a\) on both sides:

\(x=\frac{10c}{a}\)

Done.

Jeffes02  Aug 20, 2017

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