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{((b+a)/2)=8, ((c+a)/2)=14, ((c+b)/2)=16, c+b+a=x}

 Nov 30, 2016
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0 a - b + c = 12 | (equation 2)
0 a+b + c = 32 | (equation 3)
Add equation 2 to equation 3:
{a + b+0 c = 16 | (equation 1)
0 a - b + c = 12 | (equation 2)
0 a+0 b+2 c = 44 | (equation 3)
Divide equation 3 by 2:
{a + b+0 c = 16 | (equation 1)
0 a - b + c = 12 | (equation 2)
0 a+0 b+c = 22 | (equation 3)
Subtract equation 3 from equation 2:
{a + b+0 c = 16 | (equation 1)
0 a - b+0 c = -10 | (equation 2)
0 a+0 b+c = 22 | (equation 3)
Multiply equation 2 by -1:
{a + b+0 c = 16 | (equation 1)
0 a+b+0 c = 10 | (equation 2)
0 a+0 b+c = 22 | (equation 3)
Subtract equation 2 from equation 1:
{a+0 b+0 c = 6 | (equation 1)
0 a+b+0 c = 10 | (equation 2)
0 a+0 b+c = 22 | (equation 3)
Collect results:
Answer: |a = 6             and                b = 10               and              c = 22

 Nov 30, 2016

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