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Solve for x:

6x2+13x+11=0

 Apr 17, 2016
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Solve for x:
6 x^2+13 x+11 = 0

 

Divide both sides by 6:
x^2+(13 x)/6+11/6 = 0

 

Subtract 11/6 from both sides:
x^2+(13 x)/6 = -11/6

 

Add 169/144 to both sides:
x^2+(13 x)/6+169/144 = -95/144

 

Write the left hand side as a square:
(x+13/12)^2 = -95/144

 

Take the square root of both sides:
x+13/12 = (i sqrt(95))/12 or x+13/12 = 1/12 (-i) sqrt(95)

 

Subtract 13/12 from both sides:
x = (i sqrt(95))/12-13/12 or x+13/12 = 1/12 (-i) sqrt(95)

 

Subtract 13/12 from both sides:
Answer: |  x = (i sqrt(95))/12-13/12     or      x = 1/12 (-i) sqrt(95)-13/12

 Apr 17, 2016

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