+81 Solve for x :
\(\log_{5} x + \log_{5} (x - 5) = 5\)
A=
B=
There are two potential roots, A and B, where .\(A \leq B.\)
+129899 log 5 x + log 5 (x -5) = 5
log 5 [ x * (x - 5) ] = 5 we have that
5^5 = x ( x - 5)
5^5 = x^2 - 5x rearrange as
x^2 - 5x - 5^5 = 0 solving this we have that
x = [5 + 5√501] / 2 or x = [ 5 - 5√501] / 2
The second answer results in the log of a negative
So....the only answer is x = [ 5 + 5√501] / 2
