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2*3^x=7*5^x

 Oct 8, 2015
 #1
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+5

2*3^x=7*5^x      rearrange as

 

(2/7)  = (5^x / 3^x) 

 

(2/7)  = (5/3)^x        take the log of both sides

 

log(2/7)  = log(5/3)^x   and we can write

 

log(2/7)  = x log(5/3)    divide both sides by log(5/3)

 

log(2 / 7) / log (5/3)  = x   ≈ -2.45

 

 

cool cool cool

 Oct 8, 2015

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