Solve for x

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Solve for x

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836

2

+1124

My second one for today:

Solve x:

2 Log x + 2 = log 900

I said:

$Log X^2 + 2 = Log 30^2$

$2Log x - 2Log 30 = -2$

$2Log {x \over 30} = -2$

$60Logx = -60$

$Log x = -1$

$x=10^-1$

$x= {1 \over 10}$

Is this correct?

juriemagic Nov 13, 2019

Best Answer

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#1

+33654

+3

Best Answer

You go wrong on your fourth line. Check: 2log(1/10) +2 =0 log(900) = 2.954

$2log_{10}x+2=log_{10}900\\ 2log_{10}x+2=log_{10}30^2\\2log_{10}x+2=2log_{10}30\\ log_{10}x+1=log_{10}30\\log_{10}x+log_{10}10=log_{10}30\\log_{10}(10x)=log_{10}30\\ 10x=30\\x = 3$

Alan Nov 13, 2019

#2

+1124

+1

Alan,

thanks again...I understand my error...thanx a million!

juriemagic Nov 13, 2019

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Alan · Answer 1 · 2019-11-13T11:51:33

You go wrong on your fourth line. Check: 2log(1/10) +2 =0 log(900) = 2.954

$2log_{10}x+2=log_{10}900\\ 2log_{10}x+2=log_{10}30^2\\2log_{10}x+2=2log_{10}30\\ log_{10}x+1=log_{10}30\\log_{10}x+log_{10}10=log_{10}30\\log_{10}(10x)=log_{10}30\\ 10x=30\\x = 3$

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