+14915 \(Solve for\ x:\\ \dfrac{a}{x-a} + \dfrac b{x-b} = \dfrac{2c}{x-c} \)
Hello Guest!
\(\dfrac{a(x-b)(x-c)+b(x-a)(x-c)}{(x-a)(x-b)(x-c)}=\dfrac{2c(x-a)(x-b)}{(x-a)(x-b)(x-c)}\)
\(a(x-b)(x-c)+b(x-a)(x-c)=2c(x-a)(x-b)\)
wolfram alpha \(⇒ \)
\(2abc-2abx-acx+ax^2-bcx+bx^2=2abc-2acx-2bcx+2cx^2\)
\(a+b-2c\neq0,\ x=\dfrac{2ab-ac-bc}{a+b+c}\)
\(b=a, c=a\)
\(x=0\)
!
