Solve for $x$: $4x^{1/3}-2 \cdot \frac{x}{x^{2/3}}=7+\sqrt[3]{x}$.
4x^(1/3) - 2 x / x^(2/3) = 7 + x^(1/3)
4x^(1/3) - 2x^(1/3) = 7 + x^(1/3)
2x^(1/3) - x^(1/3) = 7
x^(1/3) = 7 cube both sides
x = 343
