\(x=sqrt[\sqrt{1+2}\sqrt{1+3}\sqrt{1+4}]......etc.\)to infinity. Solve for x. Very difficult problem. Thanks for help.
Infinity
x=3
3=sqrt9=sqrt(1+2*4)=sqrt(1+2sqrt16)=sqrt(1+2sqrt(1+3*5))=sqrt(1+2sqrt(1+3sqrt25))=sqrt(1+2sqrt(1+3sqrt(1+4*6)))
=sqrt(1+2sqrt(1+3sqrt(1+4sqrt......)))
