solve for y ?
(4 + 2/3)/6 + y/2 = 2
\(\begin{array}{|rcll|} \hline \frac{ 4 + \frac{2}{3} } {6} + \frac{y}{2} &=& 2 \\\\ \frac{1}{6}\cdot \Big( 4 + \frac{2}{3} \Big) + \frac{y}{2} &=& 2 \quad & | \quad \cdot 6 \\\\ \frac{6}{6}\cdot \Big( 4 + \frac{2}{3} \Big) + \frac{6 y}{2} &=& 2\cdot 6 \\\\ 4 + \frac{2}{3} + 3 y &=& 12 \quad & | \quad \cdot 3 \\\\ 4\cdot 3 + \frac{2\cdot 3}{3} + 3 y\cdot 3 &=& 12 \cdot 3 \\\\ 12 + 2 + 9 y &=& 36 \\ 14 + 9 y &=& 36 \quad & | \quad -14 \\ 9y &=& 36 -14 \\ 9y &=& 22 \quad & | \quad :9 \\\\ \mathbf{y} & \mathbf{=} & \mathbf{\frac{22}{9} } \\ \hline \end{array}\)