Solve for $z$ in the following equation: $1-iz = -1 + iz$ (where $i^2 = -1$). Simplify your answer as much as possible.

A good way to solve for z is to represent it as a+bi. 

1-iz = -1+iz

2 = 2iz

1 = iz. 

1 = i(a+bi)

1 = ai-b

So a must be 0, and b must be -1. 

z = a + bi

z = 0 + -1i

z = -i

 

I hope this helped. :))

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