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Solve for z in the literal equation

2/3(z + 5) = y.

KaylaDoodlez  Oct 11, 2017

Best Answer 

 #1
avatar+7342 
+2

\(\frac23\)(z + 5)  =  y

                                                Multiply both sides of the equation by  \(\frac32\)

 \(\frac32\) *  \(\frac23\)(z+5)  =   \(\frac32\)y

 

z + 5  =  \(\frac32\)y

                                                Subtract  5  from both sides of the equation.

z  =  \(\frac32\)y - 5

hectictar  Oct 11, 2017
 #1
avatar+7342 
+2
Best Answer

\(\frac23\)(z + 5)  =  y

                                                Multiply both sides of the equation by  \(\frac32\)

 \(\frac32\) *  \(\frac23\)(z+5)  =   \(\frac32\)y

 

z + 5  =  \(\frac32\)y

                                                Subtract  5  from both sides of the equation.

z  =  \(\frac32\)y - 5

hectictar  Oct 11, 2017

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