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Solve for z in the literal equation

2/3(z + 5) = y.

 Oct 11, 2017

Best Answer 

 #1
avatar+9488 
+2

23(z + 5)  =  y

                                                Multiply both sides of the equation by  32

 32 *  23(z+5)  =   32y

 

z + 5  =  32y

                                                Subtract  5  from both sides of the equation.

z  =  32y - 5

 Oct 11, 2017
 #1
avatar+9488 
+2
Best Answer

23(z + 5)  =  y

                                                Multiply both sides of the equation by  32

 32 *  23(z+5)  =   32y

 

z + 5  =  32y

                                                Subtract  5  from both sides of the equation.

z  =  32y - 5

hectictar Oct 11, 2017

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