+0

# solve for z

0
48
2

Find all values of z such that z^4 - 4z^2 +4 = 0.

Feb 24, 2021

#1
+944
+1

Let z^2 = a, so we are solving:

a^2 - 4a + 4 = 0

(a - 2)^2 = 0

a = 2

z^2 = 2

$$\boxed{z = \pm \sqrt{2}}$$

Feb 24, 2021
#2
+266
+1

.
Feb 24, 2021