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# Solve for :

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48
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Solve for $$r$$: $$\frac{r-45}{2} = \frac{3-2r}{5}.$$

Jan 2, 2020

#1
+16
+2

Hi, when you multiply both sides by 10, you get $$5(r-45)=2(3-2r)$$ because $$10 \div 2 = 5 \text{ and } 10 \div 5 = 2$$ .

When you expand the equation you should get $$5r-225=6-4r$$.

Moving the variables to one side and constants to another you get $$9r=231$$.

Dividing both sides by 9 gets us $$r= 231\div 9$$ which equals to $$25 \frac{2}{3}$$.

-MPS101

#2
+106519
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Thanks, MPS    !!!!!

BTW.....welcome.....!!!

CPhill  Jan 2, 2020
edited by CPhill  Jan 2, 2020