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Solve for \(r\): \(\frac{r-45}{2} = \frac{3-2r}{5}.\)

 Jan 2, 2020
 #1
avatar+64 
+2

Hi, when you multiply both sides by 10, you get \(5(r-45)=2(3-2r)\) because \(10 \div 2 = 5 \text{ and } 10 \div 5 = 2\) .

When you expand the equation you should get \(5r-225=6-4r\).

Moving the variables to one side and constants to another you get \(9r=231\).

Dividing both sides by 9 gets us \(r= 231\div 9\) which equals to \(25 \frac{2}{3}\).

 

-MPS101

 #2
avatar+109563 
+1

Thanks, MPS    !!!!!

 

BTW.....welcome.....!!!

 

cool cool cool

CPhill  Jan 2, 2020
edited by CPhill  Jan 2, 2020

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