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Solve. logx+log(x+21)=2

 

A. x=4

B. x= -25

C. x=9

D. x=2

E. both a and b

 Jun 7, 2016
 #1
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logx+log(x+21)=2

 

Rewrite the left side as

 

log [ x * (x + 21)]  = 2       and 2 can be written as log 100......so we have....

 

log [x ( x + 21) ]  = log 100      we can forget the logs and solve this:

 

x ( x + 21)   = 100    simplify

 

x^2 + 21x  = 100

 

x^2 + 21x - 100  = 0  factor as

 

(x + 25) ( x - 4)  = 0

 

Setting each factor to 0, x = -25  or x = 4

 

Reject -25 since it makes the logs negative

 

x= 4 is the soultion

 

 

cool cool cool

 Jun 7, 2016

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