Solve. logx+log(x+21)=2
A. x=4
B. x= -25
C. x=9
D. x=2
E. both a and b
logx+log(x+21)=2
Rewrite the left side as
log [ x * (x + 21)] = 2 and 2 can be written as log 100......so we have....
log [x ( x + 21) ] = log 100 we can forget the logs and solve this:
x ( x + 21) = 100 simplify
x^2 + 21x = 100
x^2 + 21x - 100 = 0 factor as
(x + 25) ( x - 4) = 0
Setting each factor to 0, x = -25 or x = 4
Reject -25 since it makes the logs negative
x= 4 is the soultion