+128407
There's nothing here to "solve".....just to evaluate..
√7^(log 5) - √5^(log 7) =
[7^(1/2)]^(log 5) - [ 5^(1/2)]^(log 7)=
[ 7] ^[ (1/2)log(5) ] - [5]^[ (1/2)log(7)]
[7] ^ [log √5] - [5]^[log √7 ] note that we can write
[10^(log7)]^[log5] - [10^(log 5)]^[log 7]
10 ^(log7 * log 5) - 10^(log 5 * log 7) =
10^(log5 * log 7) - 10^(log 5 * log7) =
0
Then.....it appears that we have the property that
a^(log b) - b^(log a) = 0
