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How do you solve a system like this using substitution?

 

y = 2x + 4

3y - 4x = 6

 

I got x = 1 and y = 6, which is wrong.

 Jun 27, 2020
 #1
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since   y = 2x+4    substitute that into the second equation for 'y'

3 ( 2x+4) -4x= 6

6x+12-4x = 6

2x +12 = 6

2x = -6

x = -3          then use this value in one of th equations to find 'y''

 
 Jun 27, 2020

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