How do you solve a system like this using substitution?
y = 2x + 4
3y - 4x = 6
I got x = 1 and y = 6, which is wrong.
since y = 2x+4 substitute that into the second equation for 'y'
3 ( 2x+4) -4x= 6
6x+12-4x = 6
2x +12 = 6
2x = -6
x = -3 then use this value in one of th equations to find 'y''