Solve systems of linear equations with elimination

−9x + 4y= 6

9x + 5y = -33        just add the two equations....and we have.....

9y = -27           divide both sides by  9

y  = -3           and using either equation - I'll use the first  -  we can find x

-9x + 4(-3) = 6

-9x - 12  = 6       add 12 to both sides

-9x  = 18           divide both sides by -9

x = -2

So (x,y)  = (-2, -3)

Solve the following system: {9 x+5 y = -33 | (equation 1) 4 y-9 x = 6 | (equation 2) Add equation 1 to equation 2: {9 x+5 y = -33 | (equation 1) 0 x+9 y = -27 | (equation 2) Divide equation 2 by 9: {9 x+5 y = -33 | (equation 1) 0 x+y = -3 | (equation 2) Subtract 5 × (equation 2) from equation 1: {9 x+0 y = -18 | (equation 1) 0 x+y = -3 | (equation 2) Divide equation 1 by 9: {x+0 y = -2 | (equation 1) 0 x+y = -3 | (equation 2) Collect results: Answer: | | {x = -2 y = -3