4x(x-2)=7 let's put this in standard form
4x^2 - 8x - 7 = 0 now, using a =4, b = -8 and c = -7, we have...
x = ( -b ±√ [b^2 - 4ac] ) / 2a
x = ( 8 ±√ [64 - 4(4)(-7)] ) / 8
x = (8±√ [176]) / 8
x = [8 ±√(16*11)] / 8
x = [ 8 ± 4√11] / 8 ( divide everything by 4 )
x = [2 ± √11] / 2