+0  
 
+1
495
1
avatar+295 

solve the equation on the interval [0,360°]

cos^2(t)+2cos(t)+1=0

Deathstroke_rule  Apr 25, 2017
 #1
avatar+93038 
+3

cos^2(t)+2cos(t)+1=0       factor

 

(cos (t) + 1)  (cos (t) + 1)  = 0

 

(cos (t) + 1 ) ^2  = 0         take the square root of both sides

 

cos (t)  + 1   =  0             subtract 1 from both sides

 

cos (t)  = -1           and this occurs at   t = 180°

 

 

cool cool cool

CPhill  Apr 25, 2017

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