solve the equation on the interval 0 ≤ θ < 2π
sin^(2)(2θ )=1
Take the sqrt of both sides to get:
sin ( 2 theta) = +-1
2 theta = pi/2 3 pi /2
theta = pi/4 3pi/4
Yep.....THANX ,Chris for noting my error:
Per Chris:
we also need 5pi/4 and 7pi/4 as answers for "theta "
~EP
+36916 +36916 
