solve the following systems algebraically. A.) x+2y= 17 x-y=2 B) 4x+5y=11 2x+6y=16 C) 4x-3y=-10 x= 1/4y-1 D) 2x+y= -2x+5 3x+2y= 2x = 3y

I'll do a couple for you:

A.  x + 2y = 17

     x - y    = 2

Subtract the second equation from the first, term by term

x - x + 2y - (-y) = 17 - 2

or 3y = 15

Divide both sides by 3

y = 5

Put this back into the first equation

x +2*5 = 17

x + 10 = 17

x = 17 - 10

x = 7

B. 4x + 5y = 11

    2x + 6y = 16

Double all the terms in the second equation to get the number of x's the same as in the first equation

   4x + 12y = 32

Subtract the first equation from the third equation term by term

   4x - 4x + 12y - 5y = 32 - 11

or 7y = 21

Divide by 7

y = 3

Put this back into the first equation

4x + 5*3 = 11

4x + 15 = 11

4x = -4

x = -1

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