+0  
 
+3
230
1
avatar

cos x(2cosx^2+1)=0

Guest Mar 20, 2017
 #1
avatar+26758 
+2

I assume this is cos x*(2[cos x]^2 + 1) = 0

 

The term in brackets can never be zero, so we must have cos x = 0

 

That is x = pi/2, 3pi/2 in the range between 0 and 2pi.

 

.

Alan  Mar 20, 2017

16 Online Users

avatar
avatar

New Privacy Policy

We use cookies to personalise content and advertisements and to analyse access to our website. Furthermore, our partners for online advertising receive information about your use of our website.
For more information: our cookie policy and privacy policy.