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\($2x - 5 \le -x +12$\)

 Jul 20, 2022
 #1
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0

\(x \in \boxed{(-\infty,7/3]}\)

.
 Jul 20, 2022
 #2
avatar+74 
+1

How did u find that answer?

ILikeSushi  Jul 20, 2022
 #4
avatar+124524 
0

It is incorrect anyway   !!!!!

 

 

cool cool cool

CPhill  Jul 20, 2022
 #3
avatar+124524 
+1

2x - 5   ≤ -x + 12     rearrange as

 

2x + x  ≤  12 + 5

 

3x ≤  17

 

x ≤  17/3   

 

x  =  ( inf, 17/3 ] 

 

 

cool cool cool

 Jul 20, 2022
 #5
avatar+74 
+1

Thx!

ILikeSushi  Jul 20, 2022

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