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Solve the inequality $(s + 8)(s - 1) \le 0.$

 

Please help

 Mar 10, 2022
edited by Guest  Mar 10, 2022
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It is the area bound by the 2 zeros, which are \(s - 1 = 0 \) and \(s + 8 = 0 \)

 

Anything between these ranges work, thus the answer is \(\color{brown}\boxed{-8 \le x \le 1}\)

 Mar 10, 2022

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