7x - 4y=21 multiply both sides by 5 35x - 20y = 105 (1)
3x = 5y+4 rearrange as 3x - 5y = 4 multiply both sides by -4 -12x +20y = -16 (2)
Add (1) and (2)
23x = 89 divide both sides by 23
x = 89/23 and using (1) to find y, we have
35(89/23) - 20 y = 105
20y = 35(89/23) -105
4y = 7(89/23) - 21
y = [7(89/23) - 21] / 4 = 35/23
![]()
Solve the following system:
{7 x-4 = 21 | (equation 1)
3 x = 5 y+4 | (equation 2)
Express the system in standard form:
{7 x+0 y = 25 | (equation 1)
3 x-5 y = 4 | (equation 2)
Subtract 3/7 × (equation 1) from equation 2:
{7 x+0 y = 25 | (equation 1)
0 x-5 y = (-47)/7 | (equation 2)
Multiply equation 2 by -7:
{7 x+0 y = 25 | (equation 1)
0 x+35 y = 47 | (equation 2)
Divide equation 2 by 35:
{7 x+0 y = 25 | (equation 1)
0 x+y = 47/35 | (equation 2)
Divide equation 1 by 7:
{x+0 y = 25/7 | (equation 1)
0 x+y = 47/35 | (equation 2)
Collect results:
Answer: |
| {x = 25/7
y = 47/35
7x - 4y=21 multiply both sides by 5 35x - 20y = 105 (1)
3x = 5y+4 rearrange as 3x - 5y = 4 multiply both sides by -4 -12x +20y = -16 (2)
Add (1) and (2)
23x = 89 divide both sides by 23
x = 89/23 and using (1) to find y, we have
35(89/23) - 20 y = 105
20y = 35(89/23) -105
4y = 7(89/23) - 21
y = [7(89/23) - 21] / 4 = 35/23
![]()