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solve the system algebraically: y=x^2-6x+7 y=2x

 Apr 16, 2015

Best Answer 

 #1
avatar+130511 
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 y=x^2-6x+7      y=2x        setting the "y's" equal, we have

2x = x^2 - 6x + 7      subtract 2x from both sides

0 = x^2  - 8x + 7      factor

(x - 7) (x -1) = 0      and setting both factors to 0, we have that x = 7 and x = 1

Here's a graph of both functions and their intersection points.... https://www.desmos.com/calculator/hojlyfda8p

 

  

 Apr 16, 2015
 #1
avatar+130511 
+5
Best Answer

 y=x^2-6x+7      y=2x        setting the "y's" equal, we have

2x = x^2 - 6x + 7      subtract 2x from both sides

0 = x^2  - 8x + 7      factor

(x - 7) (x -1) = 0      and setting both factors to 0, we have that x = 7 and x = 1

Here's a graph of both functions and their intersection points.... https://www.desmos.com/calculator/hojlyfda8p

 

  

CPhill Apr 16, 2015

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