Solve the system by substitution, if possible.
{y=9x-21 3x-y=3
a. (6, 3)
b. (9,–2)
c. (–3, 10)
d. (3, 6)
e. no solutions
y=9x-21 3x-y=3
Note that we can substitute the first equation into the second for y......and we have....
3x - [ 9x - 21] = 3 simplify
3x - 9x + 21 = 3
-6x + 21 = 3 subtract 21 from each side
-6x = -18 divide both sides by -6
x = 3 and to find y....we can use y = 9(3) - 21 = 27 - 21 = 6
So {x, y} = {3 , 6}