Solve the system by the method of substitution.
| y= x^3 − x^2 +2
|
<
|
| y= x^3 + 15x + 2
a. (5, 102), (–3, –34), (0, 2)
b. (5, 102), (–1, –12)
c. (5, 102), (3, 56), (1, 18)
d. no real solution
e. (–3, –34), (1, 18)
+118653 This question does't make much sense but i will play with it... Waht are those | and < for ??
Solve the system by the method of substitution.
| y= x^3 − x^2 +2
|
<
|
| y= x^3 + 15x + 2
If y = both those, then
\(\begin{align} x^3-x^2+2&=x^3+15x+2\\ -x^2&=15x\\ 0&=x^2+15x\\ 0&=x(x+15)\\ x=0 \quad &or \quad x=-15 \end{align}\)
I have obviously not interpreted the question the way that was intended.
a. (5, 102), (–3, –34), (0, 2)
b. (5, 102), (–1, –12)
c. (5, 102), (3, 56), (1, 18)
d. no real solution
e. (–3, –34), (1, 18)
