+118723 $$\begin{array}{rlll}
2x-5y&=&3\; &(1)\\\\\\
\frac{-2}{5}x + y &=& \frac{3}{10}\qquad &(2a)\\\\
5(\frac{-2}{5}x + y) &=&5( \frac{3}{10})\qquad\\\\
-2x + 5y &=&1.5\qquad &(2b)\\\\
2x - 5y &=&-1.5\qquad &(2c)\\\\
\end{array}$$
It now becomes clear that the 2 equations are parallel lines hence there is no simultaneous solution!
I shouold have recognised this from the beginning but better late than never!
+118723 $$\begin{array}{rlll}
2x-5y&=&3\; &(1)\\\\\\
\frac{-2}{5}x + y &=& \frac{3}{10}\qquad &(2a)\\\\
5(\frac{-2}{5}x + y) &=&5( \frac{3}{10})\qquad\\\\
-2x + 5y &=&1.5\qquad &(2b)\\\\
2x - 5y &=&-1.5\qquad &(2c)\\\\
\end{array}$$
It now becomes clear that the 2 equations are parallel lines hence there is no simultaneous solution!
I shouold have recognised this from the beginning but better late than never!
